(9x-4)(2x^2-13x-7)=0

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Solution for (9x-4)(2x^2-13x-7)=0 equation: 


Simplifying
(9x + -4)(2x2 + -13x + -7) = 0

Reorder the terms:
(-4 + 9x)(2x2 + -13x + -7) = 0

Reorder the terms:
(-4 + 9x)(-7 + -13x + 2x2) = 0

Multiply (-4 + 9x) * (-7 + -13x + 2x2)
(-4(-7 + -13x + 2x2) + 9x * (-7 + -13x + 2x2)) = 0
((-7 * -4 + -13x * -4 + 2x2 * -4) + 9x * (-7 + -13x + 2x2)) = 0
((28 + 52x + -8x2) + 9x * (-7 + -13x + 2x2)) = 0
(28 + 52x + -8x2 + (-7 * 9x + -13x * 9x + 2x2 * 9x)) = 0
(28 + 52x + -8x2 + (-63x + -117x2 + 18x3)) = 0

Reorder the terms:
(28 + 52x + -63x + -8x2 + -117x2 + 18x3) = 0

Combine like terms: 52x + -63x = -11x
(28 + -11x + -8x2 + -117x2 + 18x3) = 0

Combine like terms: -8x2 + -117x2 = -125x2
(28 + -11x + -125x2 + 18x3) = 0

Solving
28 + -11x + -125x2 + 18x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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